Just make sure the exponential growth is faster than Moore's law, or they might never notice it.
At that point why not use key based authentication?
Is it time consuming though? You could probably feed it through a cutting jig at tens of centimeters per second or more, and as the other commenter said you have to cut the cables into small pieces anyways for the microwave processing.
Maybe Anon is so lonely that just chatting with women is all he needs.
To all the people choosing the garlic bread, have you considered the vampire girlfriend might be able to make you immortal by making you a vampire?
Of course being immortal sounds like it would massively suck, garlic bread all the way!
It does, but (as far as I know) not for putting a newly generated password into a signup field.
Yep, even Ctrl+V didn't work. I guess I shouldn't be surprised considering it's a government site (the signup for federal student aid).
I ran into this just the other day, a site wouldn't let me paste my password into the "confirm password" field when signing up. Had to resort to editing the HTML properties because there's no way I'm manually typing in my long-ass randomly generated password.
I'm not much of a hot person unfortunately. :( But non-hot people can have good password security too!
hunter2
Are you sure? It isn't blocked for me.
I was going to, but it turns out my clipboard actually has a password in it... Think I'll sit this one out.
I think they're suggesting it would seem like the user is upvoting their own comments with an alt, which could get them banned.
Not really. A word with every meaning is meaningless itself, since it doesn't allow you to narrow down the word's intended meaning from the set of all possible meanings.
As I understand it, a very massive object sent into a black hole would, after passing the event horizon, be undetectable; the black hole would simply appear to have more mass. The gravitational field of the object doesn't disappear suddenly, it just gradually merges with the black hole's gravitational field until they appear as one mass.
With a big enough object, you'd get some gravitational waves and warping of the event horizon as it enters, but you'd still be unable to send information out because the object's energy and momentum is conserved. So, regardless of what you do on the inside of the black hole, the resulting gravitational waves will look the same from outside. (Think about a spacecraft deflecting its trajectory; it has to throw mass in the opposite direction with an equal amount of momentum).
Why are her legs so long??? Guess she really didn't skip leg day.
No, because each coefficient is its own variable; they're not constants.
Fun fact, omitting the (x-x) zero term and expanding the entire polynomial, you'd get something with 2^25 = 33,554,432 terms. May be slightly excessive!